Precalc help

Given: (sinx)^4 * (tanx)^2
Simplify so that the equation is expressed in only cosx.

sin^2 x + cos^2 x = 1
tan x = (sin x)/(cos x)

Two valuable identities that should help you here.

(sin^2 x)(sin^2 x)(tan^2 x )
(1-cos^2 x)(1 - cos^2 x)(1 + sec^2 x)
multiply 8D
(1 - 2cos^2 x + cos^4 x)(1 + sec^2 x)

oh gee I think I did something wrong.

sin^2 x + cos^2 x = 1
tan x = (sin x)/(cos x)

Two valuable identities that should help you here.

Used them, didn't help much.

EDIT: To clarify, for the simplified equation, you cannot have (cosx)^2, (cosx)^4, etc. , etc. Simplified equation must only have cosx and 1's.