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Precalc help - Printable Version +- Southperry.net (https://www.southperry.net) +-- Forum: Social (https://www.southperry.net/forumdisplay.php?fid=14) +--- Forum: Rubik's Cube (https://www.southperry.net/forumdisplay.php?fid=58) +--- Thread: Precalc help (/showthread.php?tid=36485) |
Precalc help - Imagine - 2011-01-19 Given: (sinx)^4 * (tanx)^2 Simplify so that the equation is expressed in only cosx. Precalc help - Hazzy - 2011-01-19 sin^2 x + cos^2 x = 1 tan x = (sin x)/(cos x) Two valuable identities that should help you here. Precalc help - Tay - 2011-01-19 (sin^2 x)(sin^2 x)(tan^2 x ) (1-cos^2 x)(1 - cos^2 x)(1 + sec^2 x) multiply 8D (1 - 2cos^2 x + cos^4 x)(1 + sec^2 x) oh gee I think I did something wrong. Precalc help - Imagine - 2011-01-19 Hazzy Wrote:sin^2 x + cos^2 x = 1 Used them, didn't help much. EDIT: To clarify, for the simplified equation, you cannot have (cosx)^2, (cosx)^4, etc. , etc. Simplified equation must only have cosx and 1's. |