Calclueless...

I don't expect to get replies in time, but oh well.

Integral of (x-1)/(x^2-4x+5) dx. How?

x - 1 is the same as x - 2 +1. That should give you a hint. Also, you'll need to complete the square for this question.

[COLOR="RoyalBlue"]Dunno if you still need it but...

 Spoiler

((x-2) / (x^2-4x+5)) dx+ (1 / (x^2-4x+5)) dx
1/2 (2x - 4 / (x^2-4x+5)) dx + (1 / ((x-2)^2 + 1))) dx
1/2 ln | x^2-4x+5 | + arctan (x-2) + C

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