FizzBuzz

 Pretty lame code (C++)

Code:

#include <iostream>
using namespace std;

int main() {
    for(int i = 100; i > 0; i--){
        if(i % 3 == 0){
            if(i % 5 == 0){
                cout << "FizzBuzz\n";
                continue;
            }
            else{
                cout << "Fizz\n";
                continue;
            }
        }
        if(i % 5 == 0){
            cout << "Buzz\n";
            continue;
        }
        cout << i << "\n";
    }
    return 0;
}

 Bonus points? Random generator

Code:

#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
using namespace std;

int main() {
    int randomNumbers[100];
    srand(time(NULL));
    for(int i = 0; i < 100; i++)
        randomNumbers[i] = rand() % 201;
    for(int j = 100; j > 0; j--){
        if(randomNumbers[j] % 3 == 0){
            if(randomNumbers[j] % 5 == 0){
                cout << "FizzBuzz\n";
                continue;
            }
            else{
                cout << "Fizz\n";
                continue;
            }
        }
        if(randomNumbers[j] % 5 == 0){
            cout << "Buzz\n";
            continue;
        }
        cout << randomNumbers[j] << "\n";
    }
    return 0;
}

Derp. I don't know. Even forgot a continue.

Now for a more interesting question: give an example of a string where printing the result of the standard string reverse algorithm does not give what you might consider the reverse of the string.

 ???

Can I cheat by having a \0 or \n in the string?

Yayyyy Python!

Code:

for i in range(1, 101):
    if (i % 3 == 0) and (i % 5 == 0):
        print("FizzBuzz")
    elif (i % 3 == 0):
        print("Fizz")
    elif (i % 5 == 0):
        print("Buzz")
    else:
        print(i)

Do people seriously apply for programming jobs when they can't program?!

I was worried about my programming ability when I get a job, but I can definitely write programs that are this simple with no effort o_o

As for the strings question... I'm guessing it involves a special character?

Derp. I don't know. Even forgot a continue.

Those are unnecessary.

 classic C - write-only style

Code:

#include <stdio.h>

int main(argc, argv)
int argc;
char *argv[];
{
    int i;
    for (i = 0; i < 100; i++)
    {
        if (! printf("%s%s", (i%3)?"":"Fizz", (i%5)?"":"Buzz")) printf("%d", i);
        printf("\n");
    }
    return 0;
}

Those are unnecessary.

The continues? Yes they are.

 Output without continues

Code:

Buzz
100
Fizz
99
98
97
Fizz
96
Buzz
95
94
Fizz
93
92
91
FizzBuzz
Buzz
90
89
88
Fizz
87
86
Buzz
85
Fizz
84
83
82
Fizz
81
Buzz
80
79
Fizz
78
77
76
FizzBuzz
Buzz
75
74
73
Fizz
72
71
Buzz
70
Fizz
69
68
67
Fizz
66
Buzz
65
64
Fizz
63
62
61
FizzBuzz
Buzz
60
59
58
Fizz
57
56
Buzz
55
Fizz
54
53
52
Fizz
51
Buzz
50
49
Fizz
48
47
46
FizzBuzz
Buzz
45
44
43
Fizz
42
41
Buzz
40
Fizz
39
38
37
Fizz
36
Buzz
35
34
Fizz
33
32
31
FizzBuzz
Buzz
30
29
28
Fizz
27
26
Buzz
25
Fizz
24
23
22
Fizz
21
Buzz
20
19
Fizz
18
17
16
FizzBuzz
Buzz
15
14
13
Fizz
12
11
Buzz
10
Fizz
9
8
7
Fizz
6
Buzz
5
4
Fizz
3
2
1

I would totally do the same way as Heidi's, but in the range (0, 100) instead =P.

The continues? Yes they are.

They are only necessary because you didn't use "else if".

Generally speaking, "continue" and "break" should only be used when it would require convoluted logic to avoid them, as they are a form of the dread "goto".

 Spoiler

One random thought i have about the string reverse question is that in C, if you reversed the null terminator as well, then you'd essentially have an empty string as a result of the reversing, which might not be what you expected...

Other than that, are all non printable characters fair game for this?

Not all languages support Unicode like that.