LHC Exp distribution?

With the party formula doesn't the one who does more damage gain more exp? How is that going to apply for lhc? If say a level 160 is partying with some level 130 and hes doing much more damage. Will the exp still be good with the 130's?

-Is there a certain level range you should be training with? Or can you just go leech with high levels?
-Is it better to kill a monster with 1 or 2 others only while the rest kill another? Or all 6 kill one (if u can't kill it fast enough for spawn rate?)

Party exp formula is as follows:
Exp = monster_exp * (damage_part + level_part)
where
damage_part = 0.6 * (damage_you_did / total_monster_hp)
level_part = 0.4 * (your_level / sum_of_party_levels)

Multiply by 1.5 if HS, but the total can't add up to more than 1.1x the monster's exp.

The level_part is, of course, the same for all monsters on the (single-spawn) map, regardless of who killed them. Changes just a bit when a party member levels.

The damage_part can be 0 (if you didn't hit that particular monster at all) or 0.6 of the monster's exp (if you killed it solo). However, taken over time, it's pretty much 0.6 * (your_dpm / sum_of_party_dpm).

For example, suppose a party of three attackers, A, B, and C. B and C are equal in damage, A does double their DPM.
If this party cycles the map together, all attacking the same monster, then A will do half the damage and B and C will do a quarter, for every monster.
If each solos his own monsters, A will kill twice as many as either B or C.
Either way, A will end up with 50% of the overall damage_part, and B and C with 25% each.

So, in that sense, it doesn't matter what the strategy. Saying things like "he's ks'ing me" is meaningless.
What everyone wants is for as many monsters to die, per hour, as possible. Depending on the spawn and on people's mobbing ability, this could be achieved either by moving together or by letting each have his or her own platform(s).

In addition to the above normal exp, LHC has special party bonus which is supposedly 50% * party_size * Exp (as calculated above). It didn't quite work out for me, might be that HS doesn't affect it.

Party exp formula is as follows:
Exp = monster_exp * (damage_part + level_part)
where
damage_part = 0.6 * (damage_you_did / total_monster_hp)
level_part = 0.4 * (your_level / sum_of_party_levels)

Multiply by 1.5 if HS, but the total can't add up to more than 1.1x the monster's exp.

The level_part is, of course, the same for all monsters on the (single-spawn) map, regardless of who killed them. Changes just a bit when a party member levels.

The damage_part can be 0 (if you didn't hit that particular monster at all) or 0.6 of the monster's exp (if you killed it solo). However, taken over time, it's pretty much 0.6 * (your_dpm / sum_of_party_dpm).

For example, suppose a party of three attackers, A, B, and C. B and C are equal in damage, A does double their DPM.
If this party cycles the map together, all attacking the same monster, then A will do half the damage and B and C will do a quarter, for every monster.
If each solos his own monsters, A will kill twice as many as either B or C.
Either way, A will end up with 50% of the overall damage_part, and B and C with 25% each.

So, in that sense, it doesn't matter what the strategy. Saying things like "he's ks'ing me" is meaningless.
What everyone wants is for as many monsters to die, per hour, as possible. Depending on the spawn and on people's mobbing ability, this could be achieved either by moving together or by letting each have his or her own platform(s).

In addition to the above normal exp, LHC has special party bonus which is supposedly 50% * party_size * Exp (as calculated above). It didn't quite work out for me, might be that HS doesn't affect it.

So lets say 2 ppl are at the bottom mobbing 3 ppl at the bottom are mobbing 3-4, while 2 are at the mid mobbing 2 and 1 person mobbing at the top.

Your saying it won't matter if the two at the middle decide to come down to the bottom to help kill faster?

It seems to me like its only faster for everyone to focuses on one monster IF they move around the map and work well as a team to kill every monster as fast as possible, otherwise the spawn rate seems to not even out if the ppl at the bottom are more powerful and kill faster.

Would there be a difference in exp if the bottom then when up to help the middle two if they didnt kill it yet?

Party exp formula is as follows:
Exp = monster_exp * (damage_part + level_part)
where
damage_part = 0.6 * (damage_you_did / total_monster_hp)
level_part = 0.4 * (your_level / sum_of_party_levels)

Multiply by 1.5 if HS, but the total can't add up to more than 1.1x the monster's exp.

The level_part is, of course, the same for all monsters on the (single-spawn) map, regardless of who killed them. Changes just a bit when a party member levels.

The damage_part can be 0 (if you didn't hit that particular monster at all) or 0.6 of the monster's exp (if you killed it solo). However, taken over time, it's pretty much 0.6 * (your_dpm / sum_of_party_dpm).

For example, suppose a party of three attackers, A, B, and C. B and C are equal in damage, A does double their DPM.
If this party cycles the map together, all attacking the same monster, then A will do half the damage and B and C will do a quarter, for every monster.
If each solos his own monsters, A will kill twice as many as either B or C.
Either way, A will end up with 50% of the overall damage_part, and B and C with 25% each.

So, in that sense, it doesn't matter what the strategy. Saying things like "he's ks'ing me" is meaningless.
What everyone wants is for as many monsters to die, per hour, as possible. Depending on the spawn and on people's mobbing ability, this could be achieved either by moving together or by letting each have his or her own platform(s).

In addition to the above normal exp, LHC has special party bonus which is supposedly 50% * party_size * Exp (as calculated above). It didn't quite work out for me, might be that HS doesn't affect it.

Then its better for b and c to team up on their own monster or else A will get most of their exp since a does way more damage then b and c. Looking at it as a whole, the monsters will die faster, but thats not what's important, its how much exp each person is getting that they care about.

I doubt the spawn rate and bonus will make up for b and c's 25% exp loss. All b and c is doing is making it even faster for A.

Then its better for b and c to team up on their own monster or else A will get most of their exp since a does way more damage then b and c. Looking at it as a whole, the monsters will die faster, but thats not what's important, its how much exp each person is getting that they care about.

I doubt the spawn rate and bonus will make up for b and c's 25% exp loss. All b and c is doing is making it even faster for A.

...
But if B and C kill monster 1 while A goes and kills something else, they get the same exp/hour because the monster B and C are attacking, while giving the two of them twice as much exp, takes twice as long to kill.

To put this as simply as i think possible, the best exp comes from all the party members doing the most damage they possibly can to as many mobs as they can all the time.

Or,

It's best for they part to hit as much as they can.

Let me try to make it simpler.

Bearwolves give you 3 exp per 1000 hp damage you did to them (Numbers slightly rounded off for simplicity. Also, this is before HS and party bonus). If you do 10m damage you will get 30k exp, regardless of whether you did all 10m on one bearwolf, or 1m each on 10 of them.

Additionally, you get about 3333 exp (20k split 6 ways. Could be a bit more or less depending on relative levels of party members) for each Bearwolf killed, regardless of whether you touched it or not, as long as you're at least level 117.

So: whichever strategy results in the most Bearwolves dead is the one that's best for all party members. Depending on everyone's mobility and other skills, it may be best to cycle the map as a team, or it may be best to split it up. But what's important to understand is that there are no "my kills" and "his kills", no reason to try to ks or to land a hit on "everybody's" monsters or whatever other leeching tricks. Just concentrate on maximum enemies dead in as little time as possible.

Okay... let me see if i understand this correctly now:

Lets just say 1 monster = 30k exp

Scenario 1:
A will kill twice as fast as B and C
A kills 2 monsters and gets 60k (100%)
B and C kill 1 monster and gets 15k each (50% each)

Scenario 2:
a, b, and c kills 3 monsters total (A solos 2 + b+c kill one) = 3
90k exp total
a gets 66% (19800exp), b gets 16.5% (4800exp) , c gets 16.5%
multiplied by 3:
59400 / 14000 / 14000 respectively.

Since it all depends on the damage you do. You just wanna go for whever the biggest mobs are? so as long as your going for the most damage you can dish out with your skill (mobbing 3+ monsters lets say), then you are already performing at ur max?

If what im thinking now is correct, then it doesn't seem to make much difference, then it all lies in the spawn rate, what would be faster? spawn? If its scenario one, then it seems A will get a lilttle more benefit since b and c are helping the spawn rate go up.

Also, what if A goes to help kill b and c's monster after killing 1 monster? Will that affect b and c' exp?

This is all based on perfect timing though, in maple, theres some traveling / spawn irregularities and other stuff im probably not accounting for. In the end does any of this matter?

I really don't think your comparisons are fair... how did you decide that in the time it takes A to solo 2, they'll only kill 3 total? Someone's not doing full DPS if that's the case.

There is no difference in exp gains for any player between
A kills 2 monsters solo
B, C each kill 1 monster solo

A kills 2 monsters solo
B, C work together to kill 2 monsters

A, B, C work together to kill 4 monsters

These 3 options will give the same exp to everyone involved, and take the same amount of attacking time. The only question is how efficiently they're using the map - less time between killing 1 monster and starting to attack the next is better.

I really don't think your comparisons are fair... how did you decide that in the time it takes A to solo 2, they'll only kill 3 total? Someone's not doing full DPS if that's the case.

There is no difference in exp gains for any player between
A kills 2 monsters solo
B, C each kill 1 monster solo

A kills 2 monsters solo
B, C work together to kill 2 monsters

A, B, C work together to kill 4 monsters

These 3 options will give the same exp to everyone involved, and take the same amount of attacking time. The only question is how efficiently they're using the map - less time between killing 1 monster and starting to attack the next is better.

A was meant to have double b and c's combined attack power. Not just double one of them*

I still think its not as simple as this. If b or c acts as a rusher, then one of them will get less exp then the other two. These calculations are only based on them both equally attacking or dealing as much damage.

But say b and c only acted rushers for A who mobb 4 at a time, and already killed off say 50-75% of its hp, then b and c come in, to help kill it off before rushing more again, b and c would be losing out even though they are killing the mobs off faster.