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How much DEX is one Attack?
#1
For my Wind Archer I'm currently using a +10 DEX Icarus Cape (2).

Although, I have +2 Attack, +8 LUK Pink Adventurer Cape.

Knowing the LUK won't do anything, would the PAC still be better to use?
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#2
What's your current DEX, STR, and wAtk? All of these matter. I'll edit the post when you provide these.

Code:
[B]Maximum Damage for Bow[/B] = (DEX*3.4 + STR)*(wAtk/100)

Assume wAtk = 100, DEX = 400, and STR = 50.  Mostly arbitrary.

(400*3.4 + 50)*(100/100)

Assign variables [I]x[/I] and [I]y[/I] to represent changes in DEX and wAtk respectively.

((DEX + [I]x[/I])*3.4 + STR)*(wAtk/100) =  ((DEX)*3.4 + STR)*((wAtk + [I]y[/I])/100)

This is to create a sort of slide ruler to determine the amount of change
on one stat that will equal the other.
Assume [I]y[/I] = 2, to represent the PAC's wAtk.

((400 + [I]x[/I])*3.4 + 50)*(100/100) = (400*3.4 + 50)*((100 + 2)/100)
            (400 + [I]x[/I])*3.4 + 50 = 1410*(102/100)
             1360 + 3.4*[I]x[/I] + 50 = 1438.2
                         3.4*[I]x[/I] = 28.2
                             [I]x[/I] = [B][color=Red]8.2941176470588235294117647058824 DEX[/color][/B]

In the above example, it only takes 9 DEX to beat 2 wAtk.
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#3
[Image: maple0039z.jpg]

There's a picture of my stats. Smile
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#4
try this

http://sapphire8.webs.com/dexatkcalculator.htm
i use it lots
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#5
-solves for the variable-
(DEX + x)*3.4 + STR = (DEX*3.4 + STR)*(ATK + 2)/ATK
(DEX + x) = ((DEX * 3.4 + STR)*(ATK + 2)/ATK - STR) / 3.4
x = (DEX + STR / 3.4)*(1 + 2/ATK) - STR / 3.4 - DEX
= (DEX + STR / 3.4)/ATK * 2

Or the above. lol

Oh. And technically speaking that's only maximum damage, though it won't make a huge difference.
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#6
MiSSHaku Wrote:[Image: maple0039z.jpg]

There's a picture of my stats. Smile

wAtk stat plz x) We're still missing that! Well, we could probably reverse calculate it or something... EDIT: 107 wAtk mirite?

I think the calculations I did earlier would be close enough for the real verdict. Stick with the DEX Icarus Cape.

(dang I wasn't too far off with arbitrary value assignment, haha)
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