Count up in a somewhat complex way

So we have hex. We have binary. We have base 110. How could I make it more complex?

By changing the bases dependant on the digit.

The base will be (distance from decimal place + 1). So the ones place will count up in base 2, the tens place will be base 3, the hundreds will be base 4, etc.

Here's an example of the first ten posts:

1
10
11
20
21
100
101
110
111
120

etc.

I shall start:

1


Yes, this will be complicated. The first digit of the number is in base 2, second in base 3, third in base 4, etc.

...
10

11

..20?

anyone who didn't understand just follow this guideline:

units digit (0 or 1 only)
tens (0 1 or 2)
hundreds (0 1 2 or 3)
.
.
.

also, yes "20" was fine


Also....


21

100

101

I assume if we reach 9987654321 (= 3.627.999 in base 10), the next one is A0000000000?

I assume if we reach 9987654321 (= 3.627.999 in base 10), the next one is A0000000000?

eyup

110

111

120

121

tooooo huntert

I didn't get it so idk what comes next, but I'll post anyway for the fun.

I didn't get it so idk what comes next, but I'll post anyway for the fun.

This is not the shenanigans.

201

210

211

220

221

300.

301