Can you solve this degeso?

But think of how you would know such an outcome in real life.

You look and see where the coins fell and what they came up as.

Easily done~

You and your friend are having a bet. He flips a nickel and a penny and hides them under a bowl while you were turned around. Your friend knows the outcome already, but you don't. Seems really difficult to guess what it landed on though... so he tells you: "At least 1 of the coins was heads." (he has to tell the truth otherwise when he removes the bowl you'll know he cheated you). To win you must guess what each different coin landed on. You want to guess that they're both heads. You're calculating the odds to see how likely you are to guess it right... (with the math from my earlier post) you realize that you have a 1/3 shot of getting it right... so if he offers you 4:1 you should take his bet

Did you know that a nickel and penny are not made of the same material? But yes this is one way.

Why does the material matter? 0.o

One of the coins is fake. Always lands on tails.

Nobody has completely gotten the correct answer. Try again.

Why would you participate in a game with such a high chance of success? Don't you know that you need to take risks to make miracles happen?

http://en.wikipedia.org/wiki/Monty_Hall_problem

similar?

Why does the material matter? 0.o

Matters more than you think because it creates multiple answers.

The only way other answers could be created would be if in your original problem HT = TH. Thus the answer would be 1/2 instead of 1/3rd. Which is just arguing sillyness really.

Don't overcomplicate things guys.
If one coin is already H, the other coin has a 50% chance of being heads or tails. The other coin is heads no matter what, so you already have Hx, x being the other coin, so the chance of them both being heads is 50% because the chance of the unflipped coin being heads is 50%, i think.

Don't overcomplicate things guys.
If one coin is already H, the other coin has a 50% chance of being heads or tails. The other coin is heads no matter what, so you already have Hx, x being the other coin, so the chance of them both being heads is 50% because the chance of the unflipped coin being heads is 50%, i think.

uh... no. It's only 50% if you know WHICH of the two coins is already a heads.

Since you dont, you have three posibilities: HH, HT, TH. So the posibility that both are heads is 1/3rd.

Why does knowing which of them is heads matter when you're already told that one of them is heads? The question is find the probability that both are heads, not find the probability of each possible situation happening. o.o

When you flip two coins here are all of the possibilities:

HH
TH
HT
TT

Case1: If you only know that one of them is Heads (but not which one), then you're left with:

HH
TH
HT

Thus P(HH)=1/3.

Case2: If you know WHICH of the coins is heads (say, the one on the left) you're left with:

HH
HT

Thus P(HH)=1/2.

In this problem, however, we're told that 1 of them is heads and not told which one... thus it's the case above and the answer is 1/3. So yeah... the wording makes a difference if you happen to know WHICH is heads, or if you just dont know.

When you flip two coins here are all of the possibilities:

HH
TH
HT
TT

Case1: If you only know that one of them is Heads (but not which one), then you're left with:

HH
TH
HT

Thus P(HH)=1/3.

Case2: If you know WHICH of the coins is heads (say, the one on the left) you're left with:

HH
HT

Thus P(HH)=1/2.

In this problem, however, we're told that 1 of them is heads and not told which one... thus it's the case above and the answer is 1/3. So yeah... the wording makes a difference if you happen to know WHICH is heads, or if you just dont know.

But what about the miracle chance of it landing on its side?

But what about the miracle chance of it landing on its side?

trololol~

<3 you

The coin COULD also spontaneously stop existing... i keep forgetting to account for that... i'm a bad math major T.T