There was an equation in Stage 1 of the Visitor event. Can someone explain to me how this works?
Seems ridiculous to bring quantum physics in a game where time travel is trivial (Neo Tokyo/City) but it seemed like an interesting topic for the Rubik's Cube.
Spoiler
I understand it's an equation about time dilation but that would imply either the player or Dr. Bing moved at fast speeds? Further, since the world itself is projected onto a single plane (the projection can be confirmed by the existence of both a world map and an atmosphere/outer space), wouldn't time be a constant for everyone in-game? I thought "magic" was the explanation for in-game physics/biology/etc.
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This is the multiplier for particles moving at v speed. At low speeds, the term is negligible, but at high speeds, the term dictates that the particle cannot travel faster than the speed of light from a fixed reference point. I'm not sure why Nexon put the equation alone in the quest, because the equation by itself does nothing. It needs to be multiplied by a rapidly moving velocity for it to mean something. I don't recall seeing anything on velocity in any part of Dr. Bing's quests.
Personally I don't think whether or not it makes sense really matters in the grand scheme of things. They just needed something complicated looking for a throwaway joke. Same thing with technobabble and whatnot.
larmie Wrote:There was an equation in Stage 1 of the Visitor event. Can someone explain to me how this works?
Seems ridiculous to bring quantum physics in a game where time travel is trivial (Neo Tokyo/City) but it seemed like an interesting topic for the Rubik's Cube.
Spoiler
I understand it's an equation about time dilation but that would imply either the player or Dr. Bing moved at fast speeds? Further, since the world itself is projected onto a single plane (the projection can be confirmed by the existence of both a world map and an atmosphere/outer space), wouldn't time be a constant for everyone in-game? I thought "magic" was the explanation for in-game physics/biology/etc.
t^1 = t / 1 - v^2 / c ^ 2
If V = velocity, and C = Chronological measurement in Years, then you have to go:
Time(in years) Divided by the square root of 1 - velocity Squared divided by Chrono squared.
It's not t to the 1st power either, lol. delta t prime in this case is the time it takes for light to trace a given path from the point of view of an observer moving at speed v.
It's not too hard to understand (I hope). Δt is the time it takes for light to travel from one arbitrary point to another arbitrary point and back. If you are not moving, and you have magic eyes that can actually follow the beam of light, you will see a straight line of movement. If, on the other hand, you were moving at velocity v while watching the same beam of light, you would see it move in a triangle. Since light moves at a constant speed, it can't somehow go faster to cover the same distance in the same amount of time. What happens instead is that time slows down for you and light traces the path at the same speed. Δt' (prime) is the amount of time that it takes for light to trace that new triangular path.
Dusk Wrote:It's not t to the 1st power either, lol. delta t prime in this case is the time it takes for light to trace a given path from the point of view of an observer moving at speed v.
It's not too hard to understand (I hope). Δt is the time it takes for light to travel from one arbitrary point to another arbitrary point and back. If you are not moving, and you have magic eyes that can actually follow the beam of light, you will see a straight line of movement. If, on the other hand, you were moving at velocity v while watching the same beam of light, you would see it move in a triangle. Since light moves at a constant speed, it can't somehow go faster to cover the same distance in the same amount of time. What happens instead is that time slows down for you and light traces the path at the same speed. Δt' (prime) is the amount of time that it takes for light to trace that new triangular path.
So it's like non-Euclidian physics. Thanks for the explanations
What if the light is moving in the same direction that you are? Then it would appear that the path of the light is actually shorter than it is from rest, not longer.
Russt Wrote:Here's something I don't quite understand...
What if the light is moving in the same direction that you are? Then it would appear that the path of the light is actually shorter than it is from rest, not longer.
You can't get shorter than a straight line. The light would just travel in a reflected triangle.
Russt Wrote:Here's something I don't quite understand...
What if the light is moving in the same direction that you are? Then it would appear that the path of the light is actually shorter than it is from rest, not longer.
That's where Einstein comes in and tells you that the time will go by slower so that the speed of light "c" isn't exceeded.
Dusk Wrote:You can't get shorter than a straight line. The light would just travel in a reflected triangle.
Light is traveling -> at 300,000,000 m/s for 1 second
You are traveling -> at 200,000,000 m/s
To your reference frame, light covers 100,000,000 m in the 1 rest-second.
?
Russt Wrote:Light is traveling -> at 300,000,000 m/s for 1 second
You are traveling -> at 200,000,000 m/s
To your reference frame, light covers 100,000,000 m in the 1 rest-second.
?
I guess an imaginary particle attached to that beam of light would be travelling through time even slower than you. There's other beams of light, though.