Get the expression for your max moment in terms of d and g for θ = 25°. Maximum load is a function of θ, but max moment, d, and g are constants with respect to θ.
Spoiler
Max moment = d*cosθ*max load*g
Given: at θ = 25, max load = 5000kg
Therefore, Max moment = d*cos25*5000*g
For different θ, max moment = d*cosθ*max load*g = d*cos25*5000*g
d and g do not change with θ, hence:
Max load = 5000cos(25)sec(θ
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Thank you, I understand what the question means now. The maximum moment is the same always (5000gdcos[25]), so as one of the variables changes (angle/max load), so must the other to get the same moment. I had no idea that that was what the question was telling me, lol.
Ok, I'm usually able to do problems like this, but I'm suffering from a cold right now and I'm tired and can't think to well. These are two Algebra 2 questions I can't solve:
1) State one solution to the system
y< 2x-1
y> or = 10-x (greater than or equal to)
2) Write a system of inequalities whose solution is the set of all points in quadrant 1 not including the axes.
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2009-10-04, 09:37 AM (This post was last modified: 2009-10-04, 10:08 AM by Tempus.)
holyforest Wrote:1) State one solution to the system
y< 2x-1
y> or = 10-x (greater than or equal to)
Either 1) plot the graphs to find the region which satisfies the equations or 2) re-write them like so:
So let's say that .
So let's say that
That's one example.
holyforest Wrote:2) Write a system of inequalities whose solution is the set of all points in quadrant 1 not including the axes.
Well the first quadrant is the one where all points are positive or 0. Since it says DON'T include the axes, we define x and y to be positive, but more than 0:
But yeah, if you were to compute pi, you'd use a Taylor series as Kajiti mentions or some other method that converges to it. I know Wikipedia has a whole list of them.
Devil's Sunrise Wrote:You cannot find all digits of pi. pi is irrational.
Doesn't stop one from trying
Case in point, people holding memory contests on the digits of pi. The winner got up to like 5 million digits or something. Somehow that almost seems like 1 gig of RAM o.O
Also, it's probably better to describe pi as transcendental, since by definition transcendental numbers, in addition to certain properties, are also irrational ones.
2009-10-07, 02:09 PM (This post was last modified: 2009-10-07, 02:16 PM by KajitiSouls.)
Devil's Sunrise Wrote:^ True, true.
(The thing is, most people know what irrational numbers are. Not everyone I know know what transcendental numbers are, for example.)
I knew that irrational numbers cannot be described by simple fractions, but I didn't know about the "cannot be represented as a decimal" part either. I always associated transcendental numbers with that latter part xD
Here's a problem...
[FLEFT][/FLEFT] In the setup shown, S is a length of cord 30'' long, and L is a rod of 20'' long. L also weighs 10 pounds. The whole entire system next to the wall is at rest.
KajitiSouls Wrote:I knew that irrational numbers cannot be described by simple fractions, but I didn't know about the "cannot be represented as a decimal" part either. I always associated transcendental numbers with that latter part xD
Well, there's always a digit after the "last" digit, else this theory would apply:
And then pi would be rational!
But yeah, pi can't be described as a root of anything either, and that's a special thing.
I find it easiest to change the sec x's to 1/cos x's. After that, just simplify by adding what's in the parenthesis (remember (sinx)^2 + (cosx)^2 = 1) and multiplying by the outer 1/cosx.
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I attempted it, and I "think" that I managed to get h in terms of one of the angles (the upper-right one), but I also managed to get the upper-right angle to be 0. So I'm gonna say that my first attempt failed miserably, lol.
Tempus Wrote:I attempted it, and I "think" that I managed to get h in terms of one of the angles (the upper-right one), but I also managed to get the upper-right angle to be 0. So I'm gonna say that my first attempt failed miserably, lol.
You can't solve for h simply because you need more info. Unless somewhere in the diagram or something says to assume that the rod is perpendicular with the wall.
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XTOTHEL Wrote:You can't solve for h simply because you need more info. Unless somewhere in the diagram or something says to assume that the rod is perpendicular with the wall.
If I write the 3 angles of the triangle as a, b and c, I can get h and T in terms of a, b and c via moments. I can't solve to get h yet, but I thought I had an equation for it that would work.
The key word is that the whole system is in equilibrium. That means all forces acting on the system (cord, rod, and wall) should intersect at one point. If that wasn't the case, there would probably be momentum left over. Taking this information, we deduce that the point of intersection is in the middle of the length of cord, which means that the bottom-most part of the system is also h distance away from where the rod is touching the wall.
h = 12.###
Wow, statics seems so much easier now lmao >.< Finding the tension in S is trivial after knowing h.