Someone please put goggles and "goggled" face to this guy

Please. I'm going to use it as avatar, and because I suck at Photoshop.. someone will have to do the work for me. I'll reward you with s and s.

+ ?

+ ?

Ooh. Me likey the orange!

+ ?

THANKS THANKS THANKS. You're the best. I ing you.

+ ?

+ =

+ =

* = ?

+ =

It makes sense...

* = ?

/

* = ?

+ =

* = ?

Well...

= -

So...

* ( - ) = ???

- = ???

+ =

* = ?

Well...

= -

So...

* ( - ) = ???

- = ???

Given:
+=

Thus, =-

² - (-) = ???
²-²-()() = ???
-()() = ???

² - (-)=-()()
Divide eq by

-+=-
=-

LOLWUT

Given:
+=

Thus, =-

² - (-) = ???
²-²-()() = ???

x^2 - x(x - y) = ???

x^2 - x^2 + xy = ???

Have to distribute the negative too, right? Or am I doing this wrong.

..how did that happen xd

x^2 - x(x - y) = ???

x^2 - x^2 + xy = ???

Have to distribute the negative too, right? Or am I doing this wrong.

Nah, I'm pretty sure you don't distribute the negative :f6:.

you do, else =-

But x*y*-1 equals -xy, but if you distirubute, it, then it equals xy.

Unless I'm just getting confused.

But x*y*-1 equals -xy, but if you distirubute, it, then it equals xy.

Unless I'm just getting confused.

In (x*y*-1) there is no distribution taking place.

Think about it this way:

x^2 - x(x - y) = ???

Let's rearrange this.

-x(x - y) + x^2 = ???

-x^2 + xy + x^2 = ???

Simplify:

xy = ???

x =

y =

* = ???

which was the original question

Guys. My head hurts. Stfu! LOL ;-;

Can someone put goggles on my avatar? I'll give them free pixels!!!! Use your imagination on the avatar. =)

what about (*2+*)-^3=?

In (x*y*-1) there is no distribution taking place.

Think about it this way:

x^2 - x(x - y) = ???

Let's rearrange this.

-x(x - y) + x^2 = ???

-x^2 + xy + x^2 = ???

Simplify:

xy = ???

x =

y =

* = ???

which was the original question

Woops, I thought you were just translating the smilies into x and y...not going from step 1 to step 2.

Yeah you're right .