2011-11-13, 11:04 AM
Perimeter of an n sided polygon with a diameter of 1.
![[Image: HEIFh.png]](http://i.imgur.com/HEIFh.png)
The size of the side of this polygon can be calculated as 2*sin(360º/2n)*(1/2) = sin(180º/n), that is taking pitagoras on half of a pizza slice of the polygon.
The total perimeter of this polygon is n * sin(180º/n)
If we take the limit of n tending to infinity we have pi.
yay~
The size of the side of this polygon can be calculated as 2*sin(360º/2n)*(1/2) = sin(180º/n), that is taking pitagoras on half of a pizza slice of the polygon.
The total perimeter of this polygon is n * sin(180º/n)
If we take the limit of n tending to infinity we have pi.
yay~