2008-10-03, 12:48 AM
1/0 is not a definite value, thus it cannot be given the state of equality with another 1/0 inside the arguments of those trigonometric functions, and the principle cannot be applied.
For the principle to work, 1/0 must equal 1/0, which is not true.
1/0 != 1/0
For the principle to work, 1/0 must equal 1/0, which is not true.
1/0 != 1/0

