2011-03-27, 10:35 AM
2147483647 Wrote:I'm actually not sure what you mean by the bolded. The range of n*cis(θin the interval [0,π
is just [-n,n) in the real plane and [0,n] in the imaginary plane. Wouldn't the real part imply that sqrt(a) can equal -a, because it's in the range?
Look at my specific interval, it doesn't include the n*cis(pi) end.


in the interval [0,π