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Local maxima/minima and removable discontinuities
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The function has no local minimum. You can't find a value for x different than zero for which the function has a minimum value (i.e. no other x in the vicinity of the first one exists for which the funcion has a lower value). There is always a value for x that you will give you a lower value of the function.
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Local maxima/minima and removable discontinuities - by Shidoshi - 2011-03-24, 06:01 PM

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