Local maxima/minima and removable discontinuities

Dammit don't you nerds sleep. I came in about to dazzle everyone and all you pineappleing people are in here already. *MAD*

Gosh. Are you guys using the quotient rule when you're doing your derivative of (x^3)/x?? Or are you just doing the derivative of x^2...

If you do the quotient rule it turns out to be 3x - x...Which is what Kalovale got by bringing the x up to -1 power and using product rule.

Dammit 21whatshisface is right. The minimum is close to 0 but not 0.

So if you use the quotient rule you end up with 3x-x... which equals 2x. Oh, so it's the same solution as using x^2, just more complicated?

Anyways, unless you can actually define a number for a local minimum, you can't use it. Can you define the number that is close to 0 but not 0 using the statement "the lowest value of f(x) is f© at x=c?"