Local maxima/minima and removable discontinuities

There are no minimas at the interval (-∞, ∞ for this function, yes. However, for any interval [ε, ∞] or [-∞, -ε], 0 < ε, there would be a local minima. Removing the infinities from the intervals will also give a local maxima.

Noah

I would disagree with you on this point. x^2 clearly has a global minimum at 0.