2011-03-23, 11:27 PM
Pretty simply:
x^2, x!=0
2x=0
x=0
The one local extreme is x=0, and since that is undefined there are no relative extrema. That's the only point it could be, and since it's undefined it can't be.
x^2, x!=0
2x=0
x=0
The one local extreme is x=0, and since that is undefined there are no relative extrema. That's the only point it could be, and since it's undefined it can't be.