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Vectors and Calculus
#11
From my book.

T = v/|v|, by definition. Rearranging gives:

v = |v| T.

Differentiating both sides of the above equation with respect to t, and using product rule:

a = v' = |v|' T + |v| T'

Also, N = T'/|T'|, by definition of N. Substituting into the above equation:

a = |v|' T + |v||T'| N

So the tangential component of acceleration is equal to |v|' and the normal component is equal to |v||T'|.
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Messages In This Thread
Vectors and Calculus - by Grey - 2011-03-19, 12:59 PM
Vectors and Calculus - by Kalovale - 2011-03-19, 06:39 PM
Vectors and Calculus - by Russt - 2011-03-19, 08:56 PM
Vectors and Calculus - by Grey - 2011-03-19, 09:13 PM
Vectors and Calculus - by 2147483647 - 2011-03-19, 11:06 PM
Vectors and Calculus - by Grey - 2011-03-20, 04:07 AM
Vectors and Calculus - by 2147483647 - 2011-03-20, 05:24 AM
Vectors and Calculus - by Grey - 2011-03-20, 06:04 AM
Vectors and Calculus - by 2147483647 - 2011-03-20, 07:00 AM
Vectors and Calculus - by Grey - 2011-03-20, 01:04 PM
Vectors and Calculus - by Russt - 2011-03-20, 03:46 PM
Vectors and Calculus - by Grey - 2011-03-22, 04:31 AM
Vectors and Calculus - by 2147483647 - 2011-03-22, 01:23 PM
Vectors and Calculus - by Grey - 2011-03-22, 04:10 PM

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