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Math Logic
#4
Code:
[p^(p=>q)]=>q
~[p^(p=>q)] v q
~p v ~(p=>q) v q
~p v (p ^ ~q) v q
~p v ~q v q
~p v 1
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Messages In This Thread
Math Logic - by Manu - 2011-03-08, 02:13 PM
Math Logic - by OB3LISK - 2011-03-08, 02:28 PM
Math Logic - by Shidoshi - 2011-03-08, 02:30 PM
Math Logic - by HellenzSin - 2011-03-08, 03:00 PM
Math Logic - by Kalovale - 2011-03-08, 03:15 PM
Math Logic - by Manu - 2011-03-08, 03:23 PM
Math Logic - by OB3LISK - 2011-03-08, 03:23 PM
Math Logic - by Kalovale - 2011-03-08, 03:32 PM
Math Logic - by HellenzSin - 2011-03-08, 03:49 PM
Math Logic - by shouri - 2011-03-08, 04:02 PM
Math Logic - by Manu - 2011-03-08, 04:11 PM
Math Logic - by HellenzSin - 2011-03-08, 04:12 PM
Math Logic - by Shidoshi - 2011-03-08, 04:15 PM
Math Logic - by HellenzSin - 2011-03-08, 04:49 PM

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