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Radiochemistry Question...
#7
For anyone interested I just did momentum balace:
Pgama² = Patom²
Egama²/c² = Erecoil * 2M

For the Erecoil it came from:
E=p²/2M (from the classical kinetic energy formula)

For the Egama it was a bit harder:
p = h/2pi * k (from quantum mechanics, duality wave-particle)
k = 2pi/lambda (definition)
E = hf = hc/lambda (energy of a wave)
Then adding all 3 together:
p=E/c


So basically Erecoil = Egama²/2Mc²
Egama = 100 keV
M = 100 * 938MeV/c² (100 nucleons on this atom)
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Messages In This Thread
Radiochemistry Question... - by Shidoshi - 2011-03-06, 11:26 AM
Radiochemistry Question... - by OB3LISK - 2011-03-06, 01:44 PM
Radiochemistry Question... - by Shidoshi - 2011-03-06, 01:52 PM
Radiochemistry Question... - by HellenzSin - 2011-03-06, 11:44 PM
Radiochemistry Question... - by Shidoshi - 2011-03-07, 05:38 AM
Radiochemistry Question... - by OB3LISK - 2011-03-07, 10:01 AM
Radiochemistry Question... - by Shidoshi - 2011-03-07, 10:32 AM

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