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Radiochemistry Question...
#4
I get E = 100000,05eV :l
Relevant http://en.wikipedia.org/wiki/M%C3%B6ssbauer_effect

Er= (Ey^2)/(2mc^2)
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Messages In This Thread
Radiochemistry Question... - by Shidoshi - 2011-03-06, 11:26 AM
Radiochemistry Question... - by OB3LISK - 2011-03-06, 01:44 PM
Radiochemistry Question... - by Shidoshi - 2011-03-06, 01:52 PM
Radiochemistry Question... - by HellenzSin - 2011-03-06, 11:44 PM
Radiochemistry Question... - by Shidoshi - 2011-03-07, 05:38 AM
Radiochemistry Question... - by OB3LISK - 2011-03-07, 10:01 AM
Radiochemistry Question... - by Shidoshi - 2011-03-07, 10:32 AM

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