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Logic Question.
#8
8 ABC

(18-8) = 10 AB
(28-8) = 20 AC
(x-8) = x-8 BC

(49-(18-8)-(28-8)-8) = 11 A
(55-(18-8)-(x-8)-8) = 45-x B
(43-(28-8)-(x-8)-8) = 23-x C

8+10+20+x-8+11+45-x+23-x = 109-x = total students with scholarships

100-(109-x) = x-9 = total students without scholarships

Which also leads me to conclude that BC can be anywhere between 15 and 1... `-`
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Messages In This Thread
Logic Question. - by OB3LISK - 2011-03-05, 08:24 AM
Logic Question. - by Shidoshi - 2011-03-05, 09:05 AM
Logic Question. - by ShinkuDragon - 2011-03-05, 09:11 AM
Logic Question. - by OB3LISK - 2011-03-05, 09:15 AM
Logic Question. - by Shidoshi - 2011-03-05, 09:18 AM
Logic Question. - by OB3LISK - 2011-03-05, 09:20 AM
Logic Question. - by Shidoshi - 2011-03-05, 09:26 AM
Logic Question. - by wobbufet - 2011-03-05, 10:04 AM
Logic Question. - by OB3LISK - 2011-03-05, 10:41 AM
Logic Question. - by OB3LISK - 2011-03-05, 11:01 AM
Logic Question. - by Shidoshi - 2011-03-05, 11:09 AM
Logic Question. - by RedRaven16 - 2011-03-05, 11:19 AM
Logic Question. - by Eos - 2011-03-05, 11:23 AM
Logic Question. - by ShinkuDragon - 2011-03-05, 11:52 AM
Logic Question. - by Manu - 2011-03-05, 12:34 PM
Logic Question. - by Shidoshi - 2011-03-05, 12:37 PM
Logic Question. - by KajitiSouls - 2011-03-05, 02:54 PM
Logic Question. - by Manu - 2011-03-05, 02:57 PM
Logic Question. - by OB3LISK - 2011-03-05, 04:13 PM

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