2011-03-05, 10:04 AM
8 ABC
(18-8) = 10 AB
(28-8) = 20 AC
(x-8) = x-8 BC
(49-(18-8)-(28-8)-8) = 11 A
(55-(18-8)-(x-8)-8) = 45-x B
(43-(28-8)-(x-8)-8) = 23-x C
8+10+20+x-8+11+45-x+23-x = 109-x = total students with scholarships
100-(109-x) = x-9 = total students without scholarships
Which also leads me to conclude that BC can be anywhere between 15 and 1... `-`
(18-8) = 10 AB
(28-8) = 20 AC
(x-8) = x-8 BC
(49-(18-8)-(28-8)-8) = 11 A
(55-(18-8)-(x-8)-8) = 45-x B
(43-(28-8)-(x-8)-8) = 23-x C
8+10+20+x-8+11+45-x+23-x = 109-x = total students with scholarships
100-(109-x) = x-9 = total students without scholarships
Which also leads me to conclude that BC can be anywhere between 15 and 1... `-`

