2011-03-05, 09:26 AM
What is sure:
A = 11
AB = 10
AC = 20
ABC = 8
From that we take that:
C+BC = 15
B+BC = 37
B+C+BC = 51 (we have 51 more sophomores to distribute around)
So either we take BC = 15 and we have B = 12 and C = 0, leaving us with 14 students without scholarships.
Or we take the other extreme at BC = 1, C = 14, B = 36, leaving us with 0 students without scholarships.
Or anything inbetween.
A = 11
AB = 10
AC = 20
ABC = 8
From that we take that:
C+BC = 15
B+BC = 37
B+C+BC = 51 (we have 51 more sophomores to distribute around)
So either we take BC = 15 and we have B = 12 and C = 0, leaving us with 14 students without scholarships.
Or we take the other extreme at BC = 1, C = 14, B = 36, leaving us with 0 students without scholarships.
Or anything inbetween.

