using the sums and differences of cubes on (A^3 + B^3)(A^3 - B^3), you get
= (a+b)(a-b)(a²-ab+b²)(a²+ab+b²)
remember that fiel said
Let A = (a + b)
Let B = (a - b)
so that mess actually looks like
[(a+b)+(a-b)] x [(a+b)-(a-b)] x [(a+b)²-(a+b)(a-b)+(a-b)²] x [(a+b)²+(a+b)(a-b)+(a-b)²]
simplify it from there since its just a bunch of plus' and minus'. also because its plus' and minus', a buttload of things should cancel out.
= (a+b)(a-b)(a²-ab+b²)(a²+ab+b²)
remember that fiel said
Let A = (a + b)
Let B = (a - b)
so that mess actually looks like
[(a+b)+(a-b)] x [(a+b)-(a-b)] x [(a+b)²-(a+b)(a-b)+(a-b)²] x [(a+b)²+(a+b)(a-b)+(a-b)²]
simplify it from there since its just a bunch of plus' and minus'. also because its plus' and minus', a buttload of things should cancel out.