2011-01-12, 02:10 AM
dy/dx=(6x^2)(y-5)
dy/(y-5) = 6 x^2 dx
integrate
ln (y-5) = 2 * x^3 +C
y-5 = e^ (2 * x^3) * e^C
y-5 = c* e^ (2 * x^3)
y = c* e^(2 * x^3) + 5
(0,8) is on the curve so...
8 = c * e^0 + 5
c = 3
^ lols
and thus
y = 3 e^(2 * x^3) +5.
dy/(y-5) = 6 x^2 dx
integrate
ln (y-5) = 2 * x^3 +C
y-5 = e^ (2 * x^3) * e^C
y-5 = c* e^ (2 * x^3)
y = c* e^(2 * x^3) + 5
(0,8) is on the curve so...
8 = c * e^0 + 5
c = 3
^ lols
and thus
y = 3 e^(2 * x^3) +5.