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Logic Challenge
Kaasoljoyyx
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#11
2010-11-11, 04:33 PM
Easy, all perfect squares of the form f(x) = x^2 are left open where x is an integer greater than 0.

Take the square root of the number, in this case it's 1*10^6, which simpliy equates to 1,000. In the case of a decimal, round down.

So what Jean/mondays said.
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Messages In This Thread
Logic Challenge - by Shidoshi - 2010-11-11, 01:17 PM
Logic Challenge - by Mute - 2010-11-11, 01:20 PM
Logic Challenge - by butterfλi - 2010-11-11, 01:40 PM
Logic Challenge - by Nikkey - 2010-11-11, 02:30 PM
Logic Challenge - by Salguod - 2010-11-11, 02:55 PM
Logic Challenge - by Jedward - 2010-11-11, 02:57 PM
Logic Challenge - by KaidaTan - 2010-11-11, 04:05 PM
Logic Challenge - by Kalovale - 2010-11-11, 04:14 PM
Logic Challenge - by Shidoshi - 2010-11-11, 04:17 PM
Logic Challenge - by Kalovale - 2010-11-11, 04:29 PM
Logic Challenge - by Kaasoljoyyx - 2010-11-11, 04:33 PM
Logic Challenge - by Kalovale - 2010-11-11, 04:51 PM
Logic Challenge - by WayOfTime - 2010-11-11, 05:04 PM
Logic Challenge - by Solarboy - 2010-11-11, 06:14 PM
Logic Challenge - by Shidoshi - 2010-11-11, 06:18 PM
Logic Challenge - by Takebacker - 2010-11-11, 06:18 PM
Logic Challenge - by ¬Rob - 2010-11-11, 06:41 PM
Logic Challenge - by Solarboy - 2010-11-11, 06:42 PM
Logic Challenge - by Mute - 2010-11-11, 07:09 PM
Logic Challenge - by Daku - 2010-11-11, 07:10 PM
Logic Challenge - by Kunagisa - 2010-11-11, 07:11 PM
Logic Challenge - by Stereo - 2010-11-11, 07:15 PM
Logic Challenge - by Kunagisa - 2010-11-11, 07:21 PM
Logic Challenge - by Hanabira.Kage - 2010-11-11, 11:49 PM
Logic Challenge - by Russt - 2010-11-12, 12:14 AM

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