2010-08-18, 12:09 AM
(This post was last modified: 2010-08-18, 09:37 PM by 2147483647.)
According to the Wikipedia article, the calculation of the probability of winning, which is also factored into the whole equation, changes depending on previous games. Is there a base formula that works so that the K value is the only missing multiplier?
More results:
At no point did either my opponent or I leave the game until the end of this table.
More results:
| Game | Player 1 | Player 2 | Who Started? | Score Difference | ||
|---|---|---|---|---|---|---|
| 1 | 2501 | +6 | 2394 | -6 | 1 | 107 |
| 2 | 2507 | +15 | 2388 | -15 | 2 | 119 |
| 3 | 2522 | -16 | 2373 | +16 | 2 | 149 |
| 4 | 2506 | +5 | 2389 | -5 | 1 | 117 |
| 5 | 2511 | -15 | 2384 | +15 | 2 | 127 |
| 6 | 2496 | +6 | 2399 | -6 | 1 | 97 |
| 7 | 2502 | -14 | 2393 | +14 | 2 | 109 |
| 8 | 2488 | +7 | 2407 | -7 | 1 | 81 |
| 9 | 2495 | +16 | 2400 | -16 | 2 | 95 |
| 10 | 2511 | +14 | 2384 | -14 | 2 | 127 |
| 11 | 2525 | -16 | 2370 | +16 | 2 | 155 |
| 12 | 2509 | +5 | 2386 | -5 | 1 | 123 |
| 13 | 2514 | +14 | 2381 | -14 | 2 | 133 |
| 14 | 2528 | -16 | 2367 | +16 | 2 | 161 |
| 15 | 2512 | -24 | 2383 | +24 | 1 | 129 |
| 16 | 2488 | +7 | 2407 | -7 | 1 | 81 |
| 17 | 2495 | -13 | 2400 | +13 | 2 | 95 |
| 18 | 2482 | +7 | 2413 | -7 | 1 | 69 |
| 19 | 2489 | -13 | 2406 | +13 | 2 | 83 |
| 20 | 2476 | 0 | 2419 | 0 | 1 | 57 |
At no point did either my opponent or I leave the game until the end of this table.