Full Meso Explosion Formula

I have never seen a ME formula before now. A few questions on that formula.

Is SkillData->nX the mastery written in the description times 10?

You said that mastery is always 0.5. That means randNum is always a pretty small number compared to 20 mil? Idk how aRandom works, but if you modulo 10mil a number, it seems to me that the result could be up to 9,999,999, which would give an end mastery of [0.5,1.0[
randNum = aRandom[nIdx++ % 7] % 10,000,000;
mastery = (double)randNum / 20,000,000 + 0.5;

You said it might be better in dps to get ME to 30 to boom all 20 bags. But what if you dropped 320 bags, which is an exact number of bags for both lvl 20 and lvl 30? Assuming 50k per bag, you would get 378k/boom over 20 booms with lvl 20, but only 339k/boom over 16 booms for lvl 30? It seems to me that it would cost 25% more time to drop the meso and yield lower damage over time to have max ME if you take the number of bags dropped to infinity.

I had a few damages gathered from blowing pap 2nd body and griffeys, by measuring the hp bars. I got
783646
901192
763850
809897
669045
total damage with max ME and 20*20k bags,
796354
total damage with max ME and 20*50k bags.
Those are much higher than your formula. Taken in March 2009, in case formula changed since then.

Is there a formula that would give how the numbers are displayed on the monsters? They don't agree with the damage done nor your formula.

Long post and lots of questions. I hope I have the concept right.