2010-07-21, 12:45 AM
Hazzy Wrote:Find a calculator that can process this to a non-zero number.
Code:(1/(sqrt(2*pi)))*e^((-220^2)/(2))
Google can't.
4.7 * 10^(-10511) xD
It's more likely to pass 10,510 10% scrolls in a row than it is to get 750mil from a unique sack.


