The math help thread

Ah thanks, I could have figured that out... but is nothing done with h, then? That's what threw me off when it comes to plugging numbers into x.

EDIT: Hold on, how did you go from (3(1+2h+h^2)-3)/h to (3+6h+h^2-3)/h?

lol made an mistake.
(3(1+2h+h^2)-3)/h = (3+6h+3h^2-3)/h

final answer = 6+3h

h is a variable, so the slope would be different depending on what h is.