The math help thread

slope = (f(1+h)-f(1))/1+h-1

=(3(1+h)^2-3(1)^2)/h

=(3(1+2h+h^2)-3)/h

=(3+6h+h^2-3)/h

=6+h

Ah thanks, I could have figured that out... but is nothing done with h, then? That's what threw me off when it comes to plugging numbers into x.

EDIT: Hold on, how did you go from (3(1+2h+h^2)-3)/h to (3+6h+h^2-3)/h?