2010-04-09, 02:09 AM
[merged post]
Okay, I'm going to assume you know what Voltorb Flip is.
if the 2 numbers add up to 5, don't touch it
if you subtract Voltorbs from 5, then thats how many squares have coins. how many coins are there in that row? using this information, you can find out the possible coin arrangements.
the spot that intercepts the row that has the most coins on both the x and y axis is the most likely spot on the board to have a coin of 2 or 3. then the one of those that has the most coins, find the point on that line that intercepts the next biggest amount of coins. repeat.
but always, 100% of the time, check if the number of squares not opened, and not voltorb, so like, if its 1 voltorb and 10 coins, and you've flipped 3 3's, you can deduce the last one is going to be a one, easily. but if you follow the method i just told you, you can always carelessly hit a voltorb when the only thing left in the row is a 1. It would be worthless to do that, you didn't even have a chance to get a 2 or 3. so, make sure you're getting the best odds to get a number.
Sometimes there will be 2 identical sets [coin/volt] in the same axe, and in the other axe, if using my method, a big amount of coin, and the first axe both would be the highest. It's all luck here, there's no way to find which one will/will not have a coin. it's all luck there.
Also, use common sense, and simple math, in order to find the places that most likely have coins. I'll update with examples in a minute.
Okay, I'm going to assume you know what Voltorb Flip is.
if the 2 numbers add up to 5, don't touch it
if you subtract Voltorbs from 5, then thats how many squares have coins. how many coins are there in that row? using this information, you can find out the possible coin arrangements.
the spot that intercepts the row that has the most coins on both the x and y axis is the most likely spot on the board to have a coin of 2 or 3. then the one of those that has the most coins, find the point on that line that intercepts the next biggest amount of coins. repeat.
but always, 100% of the time, check if the number of squares not opened, and not voltorb, so like, if its 1 voltorb and 10 coins, and you've flipped 3 3's, you can deduce the last one is going to be a one, easily. but if you follow the method i just told you, you can always carelessly hit a voltorb when the only thing left in the row is a 1. It would be worthless to do that, you didn't even have a chance to get a 2 or 3. so, make sure you're getting the best odds to get a number.
Sometimes there will be 2 identical sets [coin/volt] in the same axe, and in the other axe, if using my method, a big amount of coin, and the first axe both would be the highest. It's all luck here, there's no way to find which one will/will not have a coin. it's all luck there.
Also, use common sense, and simple math, in order to find the places that most likely have coins. I'll update with examples in a minute.