How do you calculate %xHKO?

its quite easy to calculate

once you have done all the damage calculation and have your
max and minimum damage:

you can have 3 types of values:
worst case scenario = deal minimum damage for all hits
best case sceniaro = deal maximum damage for all hits
normal case scenario = deal average damage for all hits = (maxDamage + minDamage)/2

then find out the monster hp:

assuming that the monster is 9 hp
your max damage is 3
your min damage is 1
your average damage is 2 (maxDamage + minDamage) / 2 = (3+1)/2 = 2

then how many hits to ko monster would be:
maxDamage = 9/3 = 3 hits ko
minDamage = 9/1 = 9 hits ko
averageDamage = 9/2 = 4.5 hits ko

then you add in the probability:

what are the probability of having 3 hits maxDamage/minDamage?
(note: maxDamge would be same as minDamge)

Not only did you bump a 4-month old thread, but with a worthless post that contributed nothing to the conversation.

They weren't looking for the average hits to KO (because that's easy to figure out, as you have shown), but rather your % chance to KO in a specific number of hits. Like, in your example of a damage range of 1-3, what's the % chance you'd KO in 2 hits, 3 hits, and 4 hits? At such small numbers, it's pretty easy to count up the possibilities. But with a range of say.... 9500-20000 on a 4-hit attack on a monster with 130k HP, it gets much more complicated.

I made a pretty good approximation (or so I'm told) of the formula for it in algebra on my Corsair calculator, but I don't know any real stats so it's not completely accurate, nor does it work at all with crits. If only someone with enough knowledge in the forum (NOAH) could share with us a method to calculate it with stats, that would be most helpful.