2009-12-02, 10:29 PM
Well technically you can get rid of the square root, because the minimum point is the same either way. That makes it a lot easier to differentiate, and then all you have is
(x - 1)^2 + (tan x - 1)^2
2 (x - 1) + 2 (tan x - 1) (sec^2 x) = 0
x - 1 + (tan x - 1) (sec^2 x) = 0
which... you're better off solving calculator-ically anyway.
(x - 1)^2 + (tan x - 1)^2
2 (x - 1) + 2 (tan x - 1) (sec^2 x) = 0
x - 1 + (tan x - 1) (sec^2 x) = 0
which... you're better off solving calculator-ically anyway.