2009-12-01, 11:19 PM
how does the 2nd magic accuracy works? (is this also antiquated?)
Stianweij's version:
Magic Accuracy = trunc(total int/10)+ trunc(luk/10) (source: Sleepywood forum)
Assuming my magic accuracy is 20... (INT=100/LUK=100)
How does the magic accuracy above (20) relates to the formula below?
Accuracy to hit 100% = (Avoid+1)(1+D/24) = (34+1)*(1+(100-68)/24) = 81.67
(** this formula is simplified by myself, slighly differs from the one found in SW thread)
Does 81.67 means I need (81.67-20) = 61.67 accuracy left in order to hit 100%?
(Assuming monster level is 100, my level is 68 and monster avoid is 34)
Min Accuracy to hit at all = Max Accuracy *10/24
Min Accuracy to hit at all = 20 * 10/24 = 8.3333 ?
Stianweij's version:
Magic Accuracy = trunc(total int/10)+ trunc(luk/10) (source: Sleepywood forum)
Assuming my magic accuracy is 20... (INT=100/LUK=100)
How does the magic accuracy above (20) relates to the formula below?
Accuracy to hit 100% = (Avoid+1)(1+D/24) = (34+1)*(1+(100-68)/24) = 81.67
(** this formula is simplified by myself, slighly differs from the one found in SW thread)
Does 81.67 means I need (81.67-20) = 61.67 accuracy left in order to hit 100%?
(Assuming monster level is 100, my level is 68 and monster avoid is 34)
Min Accuracy to hit at all = Max Accuracy *10/24
Min Accuracy to hit at all = 20 * 10/24 = 8.3333 ?

