2009-11-16, 07:44 PM
Graphed 2^(n^2)-2^n-5=0 and found the positive zero with the graphing calculator's zero thing. 1.75. o.0
Seems a bit off from 2.10.
Are you sure you can take a log of each term on one side like that?
ln(5+7)-(ln(5)+ln(7))=-1.07. That doesn't seem equal to me.
Seems a bit off from 2.10.
Are you sure you can take a log of each term on one side like that?
ln(5+7)-(ln(5)+ln(7))=-1.07. That doesn't seem equal to me.