2009-11-09, 10:51 PM
Hazzy Wrote:http://www.google.com/search?hl=en&safe=...f&oq=&aqi=
learn2google pls. :[
Since 10^-8 is tiny, and Google rounds, I'd say yea, it's 1.
I'm not sure if that's actually 1, since the i screws up everything. Darn imaginary numbers.
KajitiSouls Wrote:I have never heard of De Moirvres before o.O *googles and wikis*
The rest of you are lazy cheaters.
Code:(-sqrt(3) + [I]i[/I])^3
[B][I][U]arctan(-1/sqrt(3)) = θ = -30 degrees[/U][/I][/B]
r = sqrt(sqrt(3)^2 + 1^2) = 2
z = 2*[cos(-30) + [I]i[/I]*sin(-30)]
[2*(cos(-30) + [I]i[/I]*sin(-30))]^3 = 8*[cos(-90) + [I]i[/I]*sin(-90)] = 8*[I]i[/I]*-1
(1 - [I]i[/I])^6
arctan(-1/1) = -45 degrees
r = sqrt(2*1^2) = sqrt(2)
z = sqrt(2)*[cos(-45) + [I]i[/I]*sin(-45)]
[sqrt(2)*[cos(-45) + [I]i[/I]*sin(-45)]]^6 = 8*[cos(-270) + [I]i[/I]*sin(-270)] = 8*[I]i[/I]*1
(8*[I]i[/I]*-1) / (8*[I]i[/I]*1) = -1
Uhhh... where'd I go wrong o.O
Isn't the bolded/unerlined part supposed to be arctan 1/-sqrt(3)?


![[Image: b29923f7db2847c9f284814eca4e78a9.png]](http://upload.wikimedia.org/math/b/2/9/b29923f7db2847c9f284814eca4e78a9.png)