2009-11-09, 10:48 PM
ClawofBeta Wrote:More trig. I have no frigging clue why I can't understand trig as well as geometry and Algebra II.
Okay. So I'm using De Moivres Theorem to solve (- square root of 3 + i ) ^ 3
divided by (1 - i) ^ 6. I keep on getting one, but I'm 95% sure the answer is supposed to be i.
I have never heard of De Moirvres before o.O *googles and wikis*
The rest of you are lazy cheaters.
![[Image: b29923f7db2847c9f284814eca4e78a9.png]](http://upload.wikimedia.org/math/b/2/9/b29923f7db2847c9f284814eca4e78a9.png)
Code:
(-sqrt(3) + [I]i[/I])^3
arctan(-1/sqrt(3)) = θ = -30 degrees
r = sqrt(sqrt(3)^2 + 1^2) = 2
z = 2*[cos(-30) + [I]i[/I]*sin(-30)]
[2*(cos(-30) + [I]i[/I]*sin(-30))]^3 = 8*[cos(-90) + [I]i[/I]*sin(-90)] = 8*[I]i[/I]*-1
(1 - [I]i[/I])^6
arctan(-1/1) = -45 degrees
r = sqrt(2*1^2) = sqrt(2)
z = sqrt(2)*[cos(-45) + [I]i[/I]*sin(-45)]
[sqrt(2)*[cos(-45) + [I]i[/I]*sin(-45)]]^6 = 8*[cos(-270) + [I]i[/I]*sin(-270)] = 8*[I]i[/I]*1
(8*[I]i[/I]*-1) / (8*[I]i[/I]*1) = -1Uhhh... where'd I go wrong o.O

