2009-10-28, 12:52 AM
(This post was last modified: 2009-10-28, 01:03 AM by KajitiSouls.)
It would be nice if you said what number you got for an answer. Also, I said those numbers were diameters if you didn't understand what was going on. No one describes drill bits in terms of radius.
In the ways I've interpreted your equation so far, I've not come up with the correct answer.
EDIT: Nvm got it! Oh those tricky integrals >_> Now I am a little bit wiser.
ᴨ * [[SIZE="5"]ʃ[/SIZE]((5/8 - x)^2 - (3/8)^2)dx ,0 , 1/4] = .0900 in.^3
In the ways I've interpreted your equation so far, I've not come up with the correct answer.
EDIT: Nvm got it! Oh those tricky integrals >_> Now I am a little bit wiser.
ᴨ * [[SIZE="5"]ʃ[/SIZE]((5/8 - x)^2 - (3/8)^2)dx ,0 , 1/4] = .0900 in.^3