Take the derivative of the inclination, dy/dx, then take the arctg(dy/dx) for the angle of inclination, then multiply g = 9,81m/s² by the -sine(arctg(dy/dx)) and you have your acceleration.
That's without considering friction and considering the ball to be a point and not a rotating object.
Thought if you are not considering friction and a rotating system, you might as well use the conservation of mechanical energy.
mV²/2 + mgh = constant
That's without considering friction and considering the ball to be a point and not a rotating object.
Thought if you are not considering friction and a rotating system, you might as well use the conservation of mechanical energy.
mV²/2 + mgh = constant