How do you calculate %xHKO?

^ Actually, those outputs appear to be correct for the numbers you entered.

Quick and dirty empirical test (this is a Lua interpreter):

Code:

> function hit()
>> return math.random(2) == 2 and math.random(14167, 48745) or math.random(23613, 48745)
>> end
> for i = 1, 50 do print(hit() + hit() + hit()) end
113858
127556
72631
112086
55773
83884
113466
87781
128978
131475
119426
84046
76642
127260
93927
98370
91774
67336
105573
82533
78104
95773
82969
68301
118865
129770
100678
112979
107070
90977
95061
115384
114659
88434
103860
91419
86059
95861
68483
106536
109068
90778
86914
100392
100511
111596
75410
114003
101673
108739
> num = 0; for i = 1, 100000 do
>> if hit() + hit() + hit() > 85000 then num = num + 1 end
>> end; print(num)
84673
> function hit()
>> return math.random(2) == 2 and math.random(14167, 29247) or math.random(23613, 48745)
>> end
> num = 0; for i = 1, 100000 do
>> if hit() + hit() + hit() > 85000 then num = num + 1 end
>> end; print(num)
52602

Running for 100000 iterations, 84753 of the results are above 85000, or 84.753% chance. Reasonably close enough.

Likewise, for the left data set, it returns 52602 out of 100000.