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Parametrics...?
#2
Putting it into a calculator should be straightforward. Just set it to parametric mode.

Basically, instead of a function taking one argument (x) and transforming it into one value (y) as in y = 5x - 2, it's a function taking one argument (t) and transforming it into two values (x, y).

So for your problem, if t = 0, x = 0^3 = 0 and y = 0 - 2 = -2.

To convert to rectangular, you want to convert it to the form "y = (something)". You know that
y = t - 2
x = t^3

Treat it as a system of equations and solve for y in terms of x.

For part 3, insert the expression containing x in the inequality -3 <= t <= 5 and solve.
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Messages In This Thread
Parametrics...? - by xLeviathan - 2009-06-02, 11:36 PM
Parametrics...? - by Spaz - 2009-06-02, 11:52 PM
Parametrics...? - by JoeTang - 2009-06-02, 11:58 PM
Parametrics...? - by xLeviathan - 2009-06-03, 12:11 AM
Parametrics...? - by JoeTang - 2009-06-03, 01:06 AM

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