Kaasoljoyyx Wrote:Wrong. You are not given the option to select a door from 2 doors, you are given the option to switch to the remaining door.
With that logic, look at the other situation I posted
You have 100 doors and you have a 1% chance of being right. I add 100 more doors. Does that make the door you chose 0.5% now? No.
I looked at it this way, you have 2 choices. Stay or switch. Effectively, you are given the option to choose from the remaining doors.
So you have 3 doors. 2/3 chance of getting a
, 1/3 chance getting the 
.Now, minus a pineapple since he eliminated a door. So now you have two choices. Stay or switch. 2 choices, 2 doors.
If you choose to stay you have a 50% chance of getting the
and if you switch yo have 50% chance of getting the . The last door was eliminated, it doesn't count any longer since you can't choose it.With your other situation if you stay you have a 1% chance still if you switch then your chance will be .5%. A little different. Except if you knew where the first 100 doors were, one containing the
, you could effectively make yourself still have a 1% chance of winning. Only if you knew which the new doors were, of course. Again, sorry if I am seeming disagreeable. I hope I am not as if you are talking with a brick wall.