KajitiSouls Wrote:Switch your door.
You have a 1/3 chance of getting the Chinchilla. Not good odds. Since the host opens a door revealing a pineapple, you are down to choosing two doors. Now since your door has a 1/3 chance of getting the Chinchilla, and the host already eliminated one door, it stands that the only door left has the Chinchilla 2/3 of the time, since you know the door you picked has the Chinchilla only 1/3 of the time.
This problem has sparked a huge raging debate amongst probability mathe-wannabes.
I don't see why it doesn't split into a 50-50 chance.
? Also,
and now, since a door was eliminated, that your door has a 2/3 chance of not having a . The numbers can be manipulated too much; just choose a door.EDIT: Another thing I can point out, you can say the other door had 1/3 chance of not getting the chinchilla. Therefore, once a door is eliminated, using that logic, you could effectivly say the other door now has a 2/3 chance of not getting the
. The numbers can go anyway you want them to, as I see it.You could make some other possible scenarios, both for or against you getting the
.