2009-03-12, 01:38 PM
It's 33%(Well, One third)
Put simply.
They have one boy. That eliminates one option.
B/G
G/B
B/B
G/G <- Cannot happen in this situation
Then we have 3 equally weighted options left, so they each have a third chance of happening, 2 options are B/G, and 1 is B/B, so 1/3 times on average, it will be 2 boys.
Put simply.
They have one boy. That eliminates one option.
B/G
G/B
B/B
G/G <- Cannot happen in this situation
Then we have 3 equally weighted options left, so they each have a third chance of happening, 2 options are B/G, and 1 is B/B, so 1/3 times on average, it will be 2 boys.