A basic Engineering Physics (vectors/forces) problem

i'm assuming it looks similar to:

f1=2.452N
m1 = .25kg
theta1 = 30 deg(from the 0)

f2= 3.433N
m2= .25kg
theta 2 = 50 deg(reversed from the 180)

X componentminus as the 2 forces are working against each other in the x direction I think)
f1cos(30)-f2cos(50)= resultant force in x direction
2.123-2.206= 0.083

Y component+ since they are working in the same y direction)
f1sin(30)+f2sin(50) = resultant force in y direction
1.226+2.630=3.856

so the final vector has an x component of 0.083, and a y component of 3.856

use Pythagorean theorem to find F of the hypotenuse(the actual resultant force amount)

making a triangle, that would be quadrant 1 where tan(thetaresultant) = 3.856/.083
or theta® ~= 88.77 degrees

finding |r| should be easy point on


didn't do any numberchecking(in bed atm in the dark), but that's how I would have approached the problem