2013-09-16, 06:53 AM
I agree, the second one is much simpler. Thanks. I pretty much have all of the calculating functions down. I have one more function to work on, and that is to copy the input file's values into an output file, with two values per line... I think I'll be saving that for last, in case I do manage to miraculously solve that.
Buuut this is getting embarrassing. I just keep running into problems I just really can't solve by myself. Programming is hard. ;__;
"Required Input/Output Formats:
Input Prompt: Enter Name of Input File:
Enter Name of Output File: "
I'd just noticed this, so I'm wondering how this needs to work. I had a premade file and had the program open that ( inF.open("NameOfFile.txt"); ) before realizing I couldn't just do that; it looks like the program needs to locate the file I want to use in case I was using a different file name.
On a side-note, I could really use some sleep right now.
Buuut this is getting embarrassing. I just keep running into problems I just really can't solve by myself. Programming is hard. ;__;
"Required Input/Output Formats:
Input Prompt: Enter Name of Input File:
Enter Name of Output File: "
I'd just noticed this, so I'm wondering how this needs to work. I had a premade file and had the program open that ( inF.open("NameOfFile.txt"); ) before realizing I couldn't just do that; it looks like the program needs to locate the file I want to use in case I was using a different file name.
Code:
int main()
{
...
ifstream inF; //Declared input file.
ofstream outF; //Declared output file.
cout << "Enter Name of Input File: " << inF << endl;
cout << "Enter Name of Output File: " << outF << endl; //PRETTY SURE THESE TWO LINES ARE WRONG.
inF.open(???); //Opens input file.
if(inF.fail()) //Checks if the file was opened successfully.
{
return 1; //Terminates program if file is not found. MAY NEED TO USE EXIT INSTEAD OF RETURN, UNSURE HOW.
}
outF.open(???); //Opens output file.
...
}On a side-note, I could really use some sleep right now.

