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Proving the convegence of the series sqrt(n)/(n^2 - 3)
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2013-02-10, 05:47 PM
I have a series sqrt(n)/(n^2 - 3) that goes from 2 to infinity, and I want to see if it converges or diverges. I tried the ratio test, the test for divergence, and the comparison test, but none of them work (I didn't use the integral test because the teacher will not have a problem where the integral is complex for most people to do). Is there any way for me to prove that the series converges or diverges?
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Proving the convegence of the series sqrt(n)/(n^2 - 3) - by Imagine - 2013-02-10, 05:47 PM
Proving the convegence of the series sqrt(n)/(n^2 - 3) - by JoeTang - 2013-02-10, 06:06 PM
Proving the convegence of the series sqrt(n)/(n^2 - 3) - by Imagine - 2013-02-10, 06:15 PM
Proving the convegence of the series sqrt(n)/(n^2 - 3) - by JoeTang - 2013-02-10, 07:26 PM
Proving the convegence of the series sqrt(n)/(n^2 - 3) - by Kalovale - 2013-02-11, 11:30 PM
Proving the convegence of the series sqrt(n)/(n^2 - 3) - by Stereo - 2013-02-12, 08:51 AM
Proving the convegence of the series sqrt(n)/(n^2 - 3) - by Declaimed - 2013-02-14, 08:50 PM
Proving the convegence of the series sqrt(n)/(n^2 - 3) - by Stereo - 2013-02-14, 08:53 PM
Proving the convegence of the series sqrt(n)/(n^2 - 3) - by Imagine - 2013-02-14, 10:25 PM
Proving the convegence of the series sqrt(n)/(n^2 - 3) - by Locked - 2013-02-17, 12:31 AM
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