Well, with binomial distribution at higher rates, the average hits/mob is about equal to
![[Image: dmg.png]](http://i422.photobucket.com/albums/pp302/DevilsSunrise/maths/dmg.png)
where:
M = Monster HP
μ=[Average Slash Damage]×n+ [Average Stab Damage] ×(n-k)
σ= (([Max Slash Damage]×n+[Max Stab Damage]×(n-k) )- ([Min Slash Damage]×n+[Min Stab Damage]×(n-k) ))/6
when np > 10 and n(1-p)>10.
If you know statistics and binomial probability, this shouldn't really surprise you
where:
M = Monster HP
μ=[Average Slash Damage]×n+ [Average Stab Damage] ×(n-k)
σ= (([Max Slash Damage]×n+[Max Stab Damage]×(n-k) )- ([Min Slash Damage]×n+[Min Stab Damage]×(n-k) ))/6
when np > 10 and n(1-p)>10.
If you know statistics and binomial probability, this shouldn't really surprise you